Chapter 15 of 15
Chapter 15: Data Through Pictures
चित्रों से आँकड़े (चित्रालेख, टैली मार्क्स एवं दण्ड आलेख) | CBSE Session 2026–27
Core Pedagogical Competencies & Concepts
- Pictographs: Visual representation of data using pictures/icons where 1 icon represents a fixed key value.
- Tally marks grouping: Groups of five (|||| with a diagonal strike through).
- Bar Graphs: Graphical displays using rectangular bars of uniform width whose heights represent quantities.
- Interpreting trends, identifying maximum/minimum values, and computing totals from charts.
- Scale: $1\text{ symbol} = 25\text{ books}$.
- (a) Storybooks: $5 \times 25 = \mathbf{125\text{ books}}$.
All Textbook Exercises & In-Text Tasks (24 Questions)
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Q1
Library Books Pictograph • Reading Data
A school library records books borrowed by students: Grade 3 (20 books), Grade 4 (35 books), Grade 5 (45 books).
(a) If a symbol 📖 represents 5 books, how many book symbols will represent Grade 3, Grade 4, and Grade 5?
(b) Which class borrowed the maximum number of books?
(c) What is the total number of books borrowed by all three classes?
[3 Marks]
(a) If a symbol 📖 represents 5 books, how many book symbols will represent Grade 3, Grade 4, and Grade 5?
(b) Which class borrowed the maximum number of books?
(c) What is the total number of books borrowed by all three classes?
✅ Step-by-Step Solution & Working
Pictograph Calculations (1 📖 = 5 Books):
• (a) Symbol Counts:
- Grade 3: 20 ÷ 5 = 4 symbols (📖📖📖📖).
- Grade 4: 35 ÷ 5 = 7 symbols.
- Grade 5: 45 ÷ 5 = 9 symbols.
• (b) Maximum Class: Grade 5 borrowed the maximum (45 books).
• (c) Grand Total: 20 + 35 + 45 = 100 books.
• (a) Symbol Counts:
- Grade 3: 20 ÷ 5 = 4 symbols (📖📖📖📖).
- Grade 4: 35 ÷ 5 = 7 symbols.
- Grade 5: 45 ÷ 5 = 9 symbols.
• (b) Maximum Class: Grade 5 borrowed the maximum (45 books).
• (c) Grand Total: 20 + 35 + 45 = 100 books.
CBSE Step-by-Step Marking Scheme
Symbols: 4, 7, 9
1.5 M
Maximum = Grade 5
0.75 M
Total = 100 books
0.75 M
Q2
Favorite Fruits Survey • Tally Marks
In a class of 30 students, the favorite fruits are: Mango (12), Apple (8), Banana (6), Orange (4).
(a) Draw a frequency table using tally marks in bundles of five (||||).
(b) What fraction of students chose Mango as their favorite fruit?
[3 Marks]
(a) Draw a frequency table using tally marks in bundles of five (
(b) What fraction of students chose Mango as their favorite fruit?
✅ Step-by-Step Solution & Working
Tally Table:
• Mango (12):|||| |||| || (12)
• Apple (8):|||| ||| (8)
• Banana (6):|||| | (6)
• Orange (4): |||| (4)
• Total: 12 + 8 + 6 + 4 = 30 students.
• (b) Mango Fraction: 12/30 = 2/5 of the class.
• Mango (12):
• Apple (8):
• Banana (6):
• Orange (4): |||| (4)
• Total: 12 + 8 + 6 + 4 = 30 students.
• (b) Mango Fraction: 12/30 = 2/5 of the class.
CBSE Step-by-Step Marking Scheme
Accurate tally representation for all 4 fruits
2.0 M
Fraction = 12/30 = 2/5
1.0 M
Q3
School Attendance Bar Chart
A bar graph shows student attendance in Grade 5 over one week:
Monday: 42, Tuesday: 45, Wednesday: 40, Thursday: 44, Friday: 38 (Class strength = 45).
(a) On which day was attendance 100% full?
(b) On which day was attendance lowest, and how many students were absent?
(c) What was the average daily attendance for the week?
[3 Marks]
Monday: 42, Tuesday: 45, Wednesday: 40, Thursday: 44, Friday: 38 (Class strength = 45).
(a) On which day was attendance 100% full?
(b) On which day was attendance lowest, and how many students were absent?
(c) What was the average daily attendance for the week?
✅ Step-by-Step Solution & Working
Data Interpretation:
• (a) 100% Attendance: Tuesday (45 students present).
• (b) Lowest Day: Friday (38 students).
- Absentees = 45 - 38 = 7 students absent.
• (c) Average Daily Attendance:
- Total attendance = 42 + 45 + 40 + 44 + 38 = 209 students.
- Average = 209 ÷ 5 = 41.8 students per day.
• (a) 100% Attendance: Tuesday (45 students present).
• (b) Lowest Day: Friday (38 students).
- Absentees = 45 - 38 = 7 students absent.
• (c) Average Daily Attendance:
- Total attendance = 42 + 45 + 40 + 44 + 38 = 209 students.
- Average = 209 ÷ 5 = 41.8 students per day.
CBSE Step-by-Step Marking Scheme
Full attendance = Tuesday
1.0 M
Lowest = Friday with 7 absentees
1.0 M
Average = 41.8 students
1.0 M
Q4
Traffic Survey at Intersection
Students counted vehicles passing a school gate in 30 minutes: Two-wheelers (60), Cars (35), Auto-rickshaws (25), Buses (10).
(a) What was the total number of vehicles counted?
(b) Which vehicle type was most common, and what percentage of total traffic did it represent?
(c) What is the ratio of Buses to Cars?
[3 Marks]
(a) What was the total number of vehicles counted?
(b) Which vehicle type was most common, and what percentage of total traffic did it represent?
(c) What is the ratio of Buses to Cars?
✅ Step-by-Step Solution & Working
Survey Analysis:
• (a) Total Vehicles: 60 + 35 + 25 + 10 = 130 vehicles.
• (b) Most Common Vehicle: Two-wheelers (60).
- Percentage = (60 ÷ 130) × 100 ≈ 46.15%.
• (c) Ratio of Buses to Cars: 10 : 35 = 2 : 7.
• (a) Total Vehicles: 60 + 35 + 25 + 10 = 130 vehicles.
• (b) Most Common Vehicle: Two-wheelers (60).
- Percentage = (60 ÷ 130) × 100 ≈ 46.15%.
• (c) Ratio of Buses to Cars: 10 : 35 = 2 : 7.
CBSE Step-by-Step Marking Scheme
Total = 130 vehicles
1.0 M
Most common = Two-wheelers (~46.2%)
1.0 M
Ratio = 2 : 7
1.0 M
Q5
Chapati Chart (Pie Chart) • Fractional Sectors
A circular Chapati Chart represents how 40 children travel to school: 1/2 walk on foot, 1/4 ride bicycles, 1/8 take the school bus, and 1/8 come by car.
(a) How many children walk on foot?
(b) How many children ride bicycles?
(c) How many children travel by school bus or car?
[3 Marks]
(a) How many children walk on foot?
(b) How many children ride bicycles?
(c) How many children travel by school bus or car?
✅ Step-by-Step Solution & Working
Fractional Calculations (Total = 40):
• (a) Walk on Foot: 1/2 of 40 = 20 children.
• (b) Bicycles: 1/4 of 40 = 10 children.
• (c) Bus or Car: 1/8 + 1/8 = 2/8 = 1/4.
- 1/4 of 40 = 10 children (5 by bus + 5 by car).
• (a) Walk on Foot: 1/2 of 40 = 20 children.
• (b) Bicycles: 1/4 of 40 = 10 children.
• (c) Bus or Car: 1/8 + 1/8 = 2/8 = 1/4.
- 1/4 of 40 = 10 children (5 by bus + 5 by car).
CBSE Step-by-Step Marking Scheme
Walk: 20 children
1.0 M
Bicycle: 10 children
1.0 M
Bus or Car: 10 children
1.0 M
Q6
Family Electricity Consumption Graph
A family's electricity bill shows units consumed over 4 months: January: 180 units, February: 160 units, March: 240 units, April: 320 units.
(a) In which month was consumption highest? Why did it increase in March and April?
(b) What was the total units consumed over the 4 months?
(c) If electricity costs ₹7 per unit, find the total bill amount for April.
[3 Marks]
(a) In which month was consumption highest? Why did it increase in March and April?
(b) What was the total units consumed over the 4 months?
(c) If electricity costs ₹7 per unit, find the total bill amount for April.
✅ Step-by-Step Solution & Working
Energy Consumption Analysis:
• (a) Highest Month: April (320 units).
- Increase reason: Onset of summer season leading to extensive usage of fans, air coolers, and refrigerators.
• (b) Total Units: 180 + 160 + 240 + 320 = 900 units.
• (c) April Bill: 320 units × ₹7 = ₹2,240.
• (a) Highest Month: April (320 units).
- Increase reason: Onset of summer season leading to extensive usage of fans, air coolers, and refrigerators.
• (b) Total Units: 180 + 160 + 240 + 320 = 900 units.
• (c) April Bill: 320 units × ₹7 = ₹2,240.
CBSE Step-by-Step Marking Scheme
Highest = April (summer explanation)
1.0 M
Total = 900 units
1.0 M
April bill = ₹2,240
1.0 M
Q7
Choosing an Appropriate Pictograph Scale
A village dairy records daily milk collection in litres: Monday (240 L), Tuesday (360 L), Wednesday (300 L), Thursday (180 L).
(a) What would be a convenient scale for a milk can symbol 🛢️ (e.g. 1 symbol = ? litres)?
(b) How many symbols will be drawn for each day using that scale?
[3 Marks]
(a) What would be a convenient scale for a milk can symbol 🛢️ (e.g. 1 symbol = ? litres)?
(b) How many symbols will be drawn for each day using that scale?
✅ Step-by-Step Solution & Working
Scale Selection:
• (a) Convenient Scale: The numbers (240, 360, 300, 180) have HCF = 60. A scale of 1 symbol 🛢️ = 60 Litres is ideal.
• (b) Symbol Count:
- Monday: 240 ÷ 60 = 4 symbols.
- Tuesday: 360 ÷ 60 = 6 symbols.
- Wednesday: 300 ÷ 60 = 5 symbols.
- Thursday: 180 ÷ 60 = 3 symbols.
• (a) Convenient Scale: The numbers (240, 360, 300, 180) have HCF = 60. A scale of 1 symbol 🛢️ = 60 Litres is ideal.
• (b) Symbol Count:
- Monday: 240 ÷ 60 = 4 symbols.
- Tuesday: 360 ÷ 60 = 6 symbols.
- Wednesday: 300 ÷ 60 = 5 symbols.
- Thursday: 180 ÷ 60 = 3 symbols.
CBSE Step-by-Step Marking Scheme
Scale: 1 symbol = 60 L
1.5 M
Counts: 4, 6, 5, 3 symbols
1.5 M
Q8
Temperature Bar Graph • Coldest and Hottest
Maximum temperatures recorded in 4 Indian cities on a May afternoon: Delhi (42°C), Mumbai (34°C), Srinagar (22°C), Chennai (38°C).
(a) Which city recorded the highest temperature?
(b) Which city recorded the lowest temperature?
(c) What is the difference in temperature between Delhi and Srinagar?
[3 Marks]
(a) Which city recorded the highest temperature?
(b) Which city recorded the lowest temperature?
(c) What is the difference in temperature between Delhi and Srinagar?
✅ Step-by-Step Solution & Working
Temperature Analysis:
• (a) Highest Temperature: Delhi (42°C).
• (b) Lowest Temperature: Srinagar (22°C).
• (c) Difference: 42°C - 22°C = 20°C difference.
• (a) Highest Temperature: Delhi (42°C).
• (b) Lowest Temperature: Srinagar (22°C).
• (c) Difference: 42°C - 22°C = 20°C difference.
CBSE Step-by-Step Marking Scheme
Highest: Delhi (42°C)
1.0 M
Lowest: Srinagar (22°C)
1.0 M
Difference = 20°C
1.0 M
Q9
Tree Plantation Drive • Pictograph
In an environmental drive, five student clubs plant trees:
Club A (25), Club B (40), Club C (35), Club D (50), Club E (30).
(a) If 🌲 represents 10 trees, draw/write the number of full and half trees for each club.
(b) Which club planted the most trees?
[3 Marks]
Club A (25), Club B (40), Club C (35), Club D (50), Club E (30).
(a) If 🌲 represents 10 trees, draw/write the number of full and half trees for each club.
(b) Which club planted the most trees?
✅ Step-by-Step Solution & Working
Scale 1 🌲 = 10 Trees (Half 🌲 = 5 Trees):
• (a) Representation:
- Club A (25): 2 full + 1 half symbol (🌲🌲🪓).
- Club B (40): 4 full symbols (🌲🌲🌲🌲).
- Club C (35): 3 full + 1 half symbol.
- Club D (50): 5 full symbols.
- Club E (30): 3 full symbols.
• (b) Highest Club: Club D with 50 trees.
• (a) Representation:
- Club A (25): 2 full + 1 half symbol (🌲🌲🪓).
- Club B (40): 4 full symbols (🌲🌲🌲🌲).
- Club C (35): 3 full + 1 half symbol.
- Club D (50): 5 full symbols.
- Club E (30): 3 full symbols.
• (b) Highest Club: Club D with 50 trees.
CBSE Step-by-Step Marking Scheme
Correct full and half symbols
2.0 M
Club D highest
1.0 M
Q10
Sports Preference • Double Bar Graph
A survey of boys and girls in Grade 5 shows their preferred sport:
• Football: Boys 18, Girls 8
• Badminton: Boys 10, Girls 16
• Cricket: Boys 20, Girls 6
(a) Which sport is most popular among boys?
(b) Which sport is most popular among girls?
(c) What is the total number of students surveyed?
[3 Marks]
• Football: Boys 18, Girls 8
• Badminton: Boys 10, Girls 16
• Cricket: Boys 20, Girls 6
(a) Which sport is most popular among boys?
(b) Which sport is most popular among girls?
(c) What is the total number of students surveyed?
✅ Step-by-Step Solution & Working
Comparative Data:
• (a) Most Popular for Boys: Cricket (20 boys).
• (b) Most Popular for Girls: Badminton (16 girls).
• (c) Grand Total:
- Total boys = 18 + 10 + 20 = 48.
- Total girls = 8 + 16 + 6 = 30.
- Combined students = 48 + 30 = 78 students.
• (a) Most Popular for Boys: Cricket (20 boys).
• (b) Most Popular for Girls: Badminton (16 girls).
• (c) Grand Total:
- Total boys = 18 + 10 + 20 = 48.
- Total girls = 8 + 16 + 6 = 30.
- Combined students = 48 + 30 = 78 students.
CBSE Step-by-Step Marking Scheme
Boys: Cricket
1.0 M
Girls: Badminton
1.0 M
Total students = 78
1.0 M
Q11
Mid-Term Exam Marks Distribution
Marks obtained by 5 friends in Mathematics (out of 50):
Aarav: 48, Divya: 42, Farhan: 45, Gurpreet: 39, Tanya: 46.
(a) Find the range of marks (Highest mark - Lowest mark).
(b) Calculate the mean (average) mark of the 5 students.
[3 Marks]
Aarav: 48, Divya: 42, Farhan: 45, Gurpreet: 39, Tanya: 46.
(a) Find the range of marks (Highest mark - Lowest mark).
(b) Calculate the mean (average) mark of the 5 students.
✅ Step-by-Step Solution & Working
Statistical Analysis:
• (a) Range:
- Highest = 48 (Aarav).
- Lowest = 39 (Gurpreet).
- Range = 48 - 39 = 9 marks.
• (b) Mean (Average):
- Sum = 48 + 42 + 45 + 39 + 46 = 220 marks.
- Average = 220 ÷ 5 = 44 marks out of 50.
• (a) Range:
- Highest = 48 (Aarav).
- Lowest = 39 (Gurpreet).
- Range = 48 - 39 = 9 marks.
• (b) Mean (Average):
- Sum = 48 + 42 + 45 + 39 + 46 = 220 marks.
- Average = 220 ÷ 5 = 44 marks out of 50.
CBSE Step-by-Step Marking Scheme
Range = 9 marks
1.5 M
Average = 44 marks
1.5 M
Q12
Rainfall Recording • Monthly Chart
A weather station records monthly monsoon rainfall in millimetres:
June: 120 mm, July: 280 mm, August: 340 mm, September: 160 mm.
(a) In which month was rainfall heaviest?
(b) What was the total seasonal rainfall recorded?
(c) What fraction of total rainfall fell in August?
[3 Marks]
June: 120 mm, July: 280 mm, August: 340 mm, September: 160 mm.
(a) In which month was rainfall heaviest?
(b) What was the total seasonal rainfall recorded?
(c) What fraction of total rainfall fell in August?
✅ Step-by-Step Solution & Working
Rainfall Data:
• (a) Heaviest Month: August (340 mm).
• (b) Total Monsoon Rainfall: 120 + 280 + 340 + 160 = 900 mm.
• (c) August Fraction: 340 / 900 = 34/90 = 17/45 of the total rainfall.
• (a) Heaviest Month: August (340 mm).
• (b) Total Monsoon Rainfall: 120 + 280 + 340 + 160 = 900 mm.
• (c) August Fraction: 340 / 900 = 34/90 = 17/45 of the total rainfall.
CBSE Step-by-Step Marking Scheme
Heaviest: August
1.0 M
Total = 900 mm
1.0 M
Fraction = 17/45
1.0 M
Q13
School Canteen Snack Sales
On Monday, a school canteen sold: Samosas (75), Sandwiches (45), Fruit Juice packs (60), Biscuits (30).
(a) What was the ratio of Samosas sold to Biscuits sold?
(b) If each sandwich costs ₹20, find the total revenue from sandwiches.
(c) Which item contributed to exactly half the number of samosa sales?
[3 Marks]
(a) What was the ratio of Samosas sold to Biscuits sold?
(b) If each sandwich costs ₹20, find the total revenue from sandwiches.
(c) Which item contributed to exactly half the number of samosa sales?
✅ Step-by-Step Solution & Working
Canteen Data:
• (a) Ratio Samosas : Biscuits: 75 : 30 = Divide by 15 = 5 : 2.
• (b) Sandwich Revenue: 45 × ₹20 = ₹900.
• (c) Half of Samosas: Samosas = 75; half is 37.5. (Or comparing to Biscuits: 30 is close to half). Looking at Fruit juice (60) vs others: Biscuits is 30.
• (a) Ratio Samosas : Biscuits: 75 : 30 = Divide by 15 = 5 : 2.
• (b) Sandwich Revenue: 45 × ₹20 = ₹900.
• (c) Half of Samosas: Samosas = 75; half is 37.5. (Or comparing to Biscuits: 30 is close to half). Looking at Fruit juice (60) vs others: Biscuits is 30.
CBSE Step-by-Step Marking Scheme
Ratio = 5 : 2
1.5 M
Sandwich revenue = ₹900
1.5 M
Q14
Pet Animal Survey • Mode of Data
Students reported their household pets: Dog (15), Cat (9), Fish (6), Bird (4), Rabbit (2).
(a) What is the 'mode' (most frequent observation) of this data set?
(b) How many more students have dogs than cats?
(c) How many total pets are owned?
[3 Marks]
(a) What is the 'mode' (most frequent observation) of this data set?
(b) How many more students have dogs than cats?
(c) How many total pets are owned?
✅ Step-by-Step Solution & Working
Statistical Properties:
• (a) Mode: Dog (with highest frequency of 15).
• (b) Dog vs Cat Difference: 15 - 9 = 6 more students have dogs.
• (c) Total Pets: 15 + 9 + 6 + 4 + 2 = 36 pets.
• (a) Mode: Dog (with highest frequency of 15).
• (b) Dog vs Cat Difference: 15 - 9 = 6 more students have dogs.
• (c) Total Pets: 15 + 9 + 6 + 4 + 2 = 36 pets.
CBSE Step-by-Step Marking Scheme
Mode = Dog
1.0 M
Difference = 6
1.0 M
Total = 36 pets
1.0 M
Q15
Bicycle Ride Distances • Bar Graph Interpretation
Five friends track their weekly cycling distance: Kabir (24 km), Leo (32 km), Maya (18 km), Nina (28 km), Omar (30 km).
(a) Who cycled the greatest distance?
(b) What was the average cycling distance of the group?
[3 Marks]
(a) Who cycled the greatest distance?
(b) What was the average cycling distance of the group?
✅ Step-by-Step Solution & Working
Working:
• (a) Greatest Distance: Leo (32 km).
• (b) Group Average:
- Sum = 24 + 32 + 18 + 28 + 30 = 132 km.
- Average = 132 ÷ 5 = 26.4 km.
• (a) Greatest Distance: Leo (32 km).
• (b) Group Average:
- Sum = 24 + 32 + 18 + 28 + 30 = 132 km.
- Average = 132 ÷ 5 = 26.4 km.
CBSE Step-by-Step Marking Scheme
Greatest = Leo (32 km)
1.5 M
Average = 26.4 km
1.5 M
Q16
Television Screen Time Survey
A survey recorded daily hours spent watching TV by 50 students:
Less than 1 hour: 12 students
1 to 2 hours: 22 students
More than 2 hours: 16 students
(a) What percentage of students watch between 1 and 2 hours daily?
(b) What fraction of students watch more than 2 hours daily?
[3 Marks]
Less than 1 hour: 12 students
1 to 2 hours: 22 students
More than 2 hours: 16 students
(a) What percentage of students watch between 1 and 2 hours daily?
(b) What fraction of students watch more than 2 hours daily?
✅ Step-by-Step Solution & Working
Calculations:
• (a) 1 to 2 Hours Percentage: (22 ÷ 50) × 100 = 44%.
• (b) More than 2 Hours Fraction: 16/50 = 8/25 of the students.
• (a) 1 to 2 Hours Percentage: (22 ÷ 50) × 100 = 44%.
• (b) More than 2 Hours Fraction: 16/50 = 8/25 of the students.
CBSE Step-by-Step Marking Scheme
Percentage = 44%
1.5 M
Fraction = 8/25
1.5 M
Q17
Mental Arithmetic • Interpreting Pictograph Symbols
On a pictograph where 1 🚗 represents 25 cars:
(a) How many cars are represented by 6 symbols?
(b) How many symbols will represent 200 cars?
(c) How many cars are represented by 3.5 symbols?
[3 Marks]
(a) How many cars are represented by 6 symbols?
(b) How many symbols will represent 200 cars?
(c) How many cars are represented by 3.5 symbols?
✅ Step-by-Step Solution & Working
Mental Calculations (1 🚗 = 25 cars):
• (a) 6 Symbols: 6 × 25 = 150 cars.
• (b) 200 Cars: 200 ÷ 25 = 8 symbols.
• (c) 3.5 Symbols: 3.5 × 25 = 75 + 12.5 = 87.5 cars (or 3 full + 1 half symbol = 75 + 12 = 87 cars).
• (a) 6 Symbols: 6 × 25 = 150 cars.
• (b) 200 Cars: 200 ÷ 25 = 8 symbols.
• (c) 3.5 Symbols: 3.5 × 25 = 75 + 12.5 = 87.5 cars (or 3 full + 1 half symbol = 75 + 12 = 87 cars).
CBSE Step-by-Step Marking Scheme
Part (a): 150 cars
1.0 M
Part (b): 8 symbols
1.0 M
Part (c): 87.5 cars
1.0 M
Q18
School Bus Seating Capacity Data
A fleet of 4 school buses has capacities and current loads:
Bus 1: Capacity 50, Load 46
Bus 2: Capacity 40, Load 38
Bus 3: Capacity 50, Load 49
Bus 4: Capacity 60, Load 55
(a) What is the total carrying capacity of the fleet?
(b) How many total students are currently traveling?
(c) How many vacant seats are there across all 4 buses?
[3 Marks]
Bus 1: Capacity 50, Load 46
Bus 2: Capacity 40, Load 38
Bus 3: Capacity 50, Load 49
Bus 4: Capacity 60, Load 55
(a) What is the total carrying capacity of the fleet?
(b) How many total students are currently traveling?
(c) How many vacant seats are there across all 4 buses?
✅ Step-by-Step Solution & Working
Data Aggregation:
• (a) Total Capacity: 50 + 40 + 50 + 60 = 200 seats.
• (b) Total Students Traveling: 46 + 38 + 49 + 55 = 188 students.
• (c) Vacant Seats: 200 - 188 = 12 vacant seats.
• (a) Total Capacity: 50 + 40 + 50 + 60 = 200 seats.
• (b) Total Students Traveling: 46 + 38 + 49 + 55 = 188 students.
• (c) Vacant Seats: 200 - 188 = 12 vacant seats.
CBSE Step-by-Step Marking Scheme
Capacity = 200 seats
1.0 M
Students = 188
1.0 M
Vacant = 12 seats
1.0 M
Q19
HOTS • Data Inference Riddle
In a class of 28 students, all students play either Chess or Carrom or both. 18 students play Chess, and 16 students play Carrom. How many students play both Chess and Carrom?
[3 Marks]
✅ Step-by-Step Solution & Working
Set Principle Formula ($N(A \cup B) = N(A) + N(B) - N(A \cap B)$):
1. Total unique students = 28.
2. Sum of individual players = 18 (Chess) + 16 (Carrom) = 34.
3. Excess count due to double-counting students who play both games = 34 - 28 = 6 students.
4. Therefore, exactly 6 students play both Chess and Carrom.
(Check: Chess only = 12, Carrom only = 10, Both = 6. 12 + 10 + 6 = 28. Verified!)
1. Total unique students = 28.
2. Sum of individual players = 18 (Chess) + 16 (Carrom) = 34.
3. Excess count due to double-counting students who play both games = 34 - 28 = 6 students.
4. Therefore, exactly 6 students play both Chess and Carrom.
(Check: Chess only = 12, Carrom only = 10, Both = 6. 12 + 10 + 6 = 28. Verified!)
CBSE Step-by-Step Marking Scheme
Sum of sets = 18 + 16 = 34
1.5 M
Students playing both = 6 with proof
1.5 M
Q20
Music Instrument Classes Enrollment
A music academy has student enrollment: Guitar (32), Keyboard (28), Drums (16), Flute (24).
(a) What is the ratio of Flute students to Guitar students?
(b) Express the Drums enrollment as a percentage of total music students.
[3 Marks]
(a) What is the ratio of Flute students to Guitar students?
(b) Express the Drums enrollment as a percentage of total music students.
✅ Step-by-Step Solution & Working
Working:
• Total students = 32 + 28 + 16 + 24 = 100 students.
• (a) Ratio Flute : Guitar: 24 : 32 = Divide by 8 = 3 : 4.
• (b) Drums Percentage: (16 ÷ 100) × 100 = 16%.
• Total students = 32 + 28 + 16 + 24 = 100 students.
• (a) Ratio Flute : Guitar: 24 : 32 = Divide by 8 = 3 : 4.
• (b) Drums Percentage: (16 ÷ 100) × 100 = 16%.
CBSE Step-by-Step Marking Scheme
Total = 100 students
1.0 M
Ratio = 3 : 4
1.0 M
Drums = 16%
1.0 M
Q21
Rainfall Days in a Year
A coastal city recorded rainy days over 4 seasons: Monsoon (65 days), Winter (12 days), Summer (8 days), Post-Monsoon (15 days).
(a) What was the total number of rainy days in the year?
(b) What fraction of rainy days occurred during the Monsoon?
[3 Marks]
(a) What was the total number of rainy days in the year?
(b) What fraction of rainy days occurred during the Monsoon?
✅ Step-by-Step Solution & Working
Calculations:
• (a) Total Rainy Days: 65 + 12 + 8 + 15 = 100 days.
• (b) Monsoon Fraction: 65/100 = 13/20 (or 65%).
• (a) Total Rainy Days: 65 + 12 + 8 + 15 = 100 days.
• (b) Monsoon Fraction: 65/100 = 13/20 (or 65%).
CBSE Step-by-Step Marking Scheme
Total = 100 days
1.5 M
Monsoon fraction = 13/20
1.5 M
Q22
Mental Arithmetic • Tally Count Extraction
Identify the numeric value of each tally group:
(a)|||| |||| |||| |||
(b)|||| |||| |
(c)|||| |||| |||| ||||
[3 Marks]
(a)
(b)
(c)
✅ Step-by-Step Solution & Working
Tally Bundle Values (Each bundle = 5):
• (a) 3 bundles + 3: (3 × 5) + 3 = 15 + 3 = 18.
• (b) 2 bundles + 1: (2 × 5) + 1 = 10 + 1 = 11.
• (c) 4 bundles: 4 × 5 = 20.
• (a) 3 bundles + 3: (3 × 5) + 3 = 15 + 3 = 18.
• (b) 2 bundles + 1: (2 × 5) + 1 = 10 + 1 = 11.
• (c) 4 bundles: 4 × 5 = 20.
CBSE Step-by-Step Marking Scheme
Part (a): 18
1.0 M
Part (b): 11
1.0 M
Part (c): 20
1.0 M
Q23
True or False with Statistics Reason
State True or False with reasoning:
(a) A bar graph must always have equal spacing between its bars.
(b) The scale of a bar graph must always start from zero.
(c) A pictograph can only display whole numbers and cannot represent fractions.
[3 Marks]
(a) A bar graph must always have equal spacing between its bars.
(b) The scale of a bar graph must always start from zero.
(c) A pictograph can only display whole numbers and cannot represent fractions.
✅ Step-by-Step Solution & Working
Justifications:
• (a) True: Equal uniform spacing between bars prevents visual distortion and maintains aesthetic and statistical consistency.
• (b) True: Starting bar graphs at zero prevents exaggerating differences between categories.
• (c) False: A pictograph can represent fractional quantities using half or partial symbols (e.g. half a symbol represents half the scale value).
• (a) True: Equal uniform spacing between bars prevents visual distortion and maintains aesthetic and statistical consistency.
• (b) True: Starting bar graphs at zero prevents exaggerating differences between categories.
• (c) False: A pictograph can represent fractional quantities using half or partial symbols (e.g. half a symbol represents half the scale value).
CBSE Step-by-Step Marking Scheme
Part (a): True with spacing reason
1.0 M
Part (b): True with baseline reason
1.0 M
Part (c): False with half-symbol proof
1.0 M
Q24
Comprehensive Data Handling Project
A class conducted an energy conservation survey recording daily hours of classroom fan usage over 5 weekdays: Mon (6 h), Tue (5 h), Wed (7 h), Thu (4 h), Fri (6 h).
(a) Construct a frequency table and find total fan hours.
(b) If each ceiling fan consumes 0.08 kWh per hour, how many kWh of energy were used in total?
(c) At ₹6 per kWh, find the electricity cost for the week.
[3 Marks]
(a) Construct a frequency table and find total fan hours.
(b) If each ceiling fan consumes 0.08 kWh per hour, how many kWh of energy were used in total?
(c) At ₹6 per kWh, find the electricity cost for the week.
✅ Step-by-Step Solution & Working
Comprehensive Project Working:
• (a) Total Hours: 6 + 5 + 7 + 4 + 6 = 28 hours.
• (b) Energy Consumed: 28 hours × 0.08 kWh = 2.24 kWh.
• (c) Total Electricity Cost: 2.24 kWh × ₹6 = ₹13.44.
• (a) Total Hours: 6 + 5 + 7 + 4 + 6 = 28 hours.
• (b) Energy Consumed: 28 hours × 0.08 kWh = 2.24 kWh.
• (c) Total Electricity Cost: 2.24 kWh × ₹6 = ₹13.44.
CBSE Step-by-Step Marking Scheme
Total fan hours = 28 h
1.0 M
Energy = 2.24 kWh
1.0 M
Cost = ₹13.44
1.0 M
🌟 NEP 2020 Competency-Based Case Study
Competency Question: Van Mahotsav Sapling Planting Audit
During the annual Van Mahotsav tree plantation drive, four houses of a school planted neem, peepal, and gulmohar saplings. Red House planted 85, Blue House planted 110, Green House planted 125, and Yellow House planted 80 saplings.
Analytical Task: (a) What is the total count of saplings planted by all four houses?
(b) By what percentage did Green House exceed Yellow House in saplings planted?
(b) By what percentage did Green House exceed Yellow House in saplings planted?
Evaluation & Model Answer:
Suggested Model Solution:
(a) Total Saplings: 85 + 110 + 125 + 80 = 400 saplings.
(b) Percentage Difference: 125 - 80/80 × 100 = 45/80 × 100 = 56.25%.
Rubric: 1M concept identification + 1M step execution + 1M conclusion