Chapter 1 of 14
Chapter 1: What's in a Name?
Letter Counting, Name Grids, Number Names & Comparing Quantities | CBSE Session 2026–27
Core Pedagogical Competencies & Concepts
- Counting letters in names and organizing data into frequency tables.
- Comparing lengths of names: identifying longest and shortest names.
- Finding names starting or ending with the same letter.
- Representing quantities using tally marks and bar-like grid representations.
All Textbook Exercises & In-Text Tasks (29 Questions)
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Q1
Textbook Exercise • Letter Counting
Write down the names of four of your classmates. Count the number of letters in each name. Which name is the longest, which is the shortest, and what is the difference between the two?
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
1. Suppose we choose 4 classmates: Ravi, Ananya, Aarav, and Dharmendra.
2. Counting letters in each:
• Ravi: R-A-V-I = 4 letters
• Ananya: A-N-A-N-Y-A = 6 letters
• Aarav: A-A-R-A-V = 5 letters
• Dharmendra: D-H-A-R-M-E-N-D-R-A = 10 letters
3. Longest name: Dharmendra (10 letters)
4. Shortest name: Ravi (4 letters)
5. Difference: 10 - 4 = 6 letters.
1. Suppose we choose 4 classmates: Ravi, Ananya, Aarav, and Dharmendra.
2. Counting letters in each:
• Ravi: R-A-V-I = 4 letters
• Ananya: A-N-A-N-Y-A = 6 letters
• Aarav: A-A-R-A-V = 5 letters
• Dharmendra: D-H-A-R-M-E-N-D-R-A = 10 letters
3. Longest name: Dharmendra (10 letters)
4. Shortest name: Ravi (4 letters)
5. Difference: 10 - 4 = 6 letters.
CBSE Step-by-Step Marking Scheme
Correct letter count for all 4 names
1.5 M
Identifying longest, shortest, and difference
1.5 M
Q2
Classroom Activity • Alphabet Hunt
In a class of 20 children, 5 names start with the letter 'A', 3 with 'R', 4 with 'S', and 8 with other letters. How many names start with 'A', 'R', or 'S' altogether? What fraction of names start with 'A'?
[3 Marks]
✅ Step-by-Step Solution & Working
Given:
• Total children = 20
• Names starting with 'A' = 5
• Names starting with 'R' = 3
• Names starting with 'S' = 4
Calculation:
• Total names starting with 'A', 'R', or 'S' = 5 + 3 + 4 = 12 names.
• Fraction of names starting with 'A' = 5 out of 20 = 5/20 = 1/4 (one-fourth).
• Total children = 20
• Names starting with 'A' = 5
• Names starting with 'R' = 3
• Names starting with 'S' = 4
Calculation:
• Total names starting with 'A', 'R', or 'S' = 5 + 3 + 4 = 12 names.
• Fraction of names starting with 'A' = 5 out of 20 = 5/20 = 1/4 (one-fourth).
CBSE Step-by-Step Marking Scheme
Correct addition of name categories (5+3+4 = 12)
1.5 M
Correct fraction identification (5/20 = 1/4)
1.5 M
Q3
Hands-on Project • Name Tally Chart
How can you organize all the students' names in your class by the number of letters (3 letters, 4 letters, 5 letters, 6+ letters) using a tally chart? Create a sample tally chart for 15 students.
[4 Marks]
✅ Step-by-Step Solution & Working
Sample Tally Chart for 15 Students:
| Name Length | Tally Marks | Number of Children |
|---|---|---|
| 3 letters (e.g., Ali, Uma) | || | 2 |
| 4 letters (e.g., Riya, John) | |||| | 4 |
| 5 letters (e.g., Mohan, Priya) | 6 | |
| 6+ letters (e.g., Deepak, Sunita) | ||| | 3 |
| Total | — | 15 |
CBSE Step-by-Step Marking Scheme
Correct layout and categories in table
2.0 M
Correct tally mark grouping (bundles of 5)
2.0 M
Q4
Animal Team Game • Comparing Length of Names
In the Animal Team Game, the captain of Team 1 has the longest name and the captain of Team 2 has the shortest name. Given the list of animals: Elephant (8 letters), Ox (2 letters), Tiger (5 letters), and Deer (4 letters):
(a) Who is the captain of Team 1 and Team 2?
(b) Can you name an animal with an even longer name than Team 1's captain?
[3 Marks]
(a) Who is the captain of Team 1 and Team 2?
(b) Can you name an animal with an even longer name than Team 1's captain?
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
(a) Identifying Captains:
• Elephant: E-L-E-P-H-A-N-T = 8 letters (Longest)
• Ox: O-X = 2 letters (Shortest)
• Team 1 Captain: Elephant (8 letters)
• Team 2 Captain: Ox (2 letters)
(b) Animal with Longer Name:
• Yes! Crocodile (C-R-O-C-O-D-I-L-E = 9 letters) or Hippopotamus (H-I-P-P-O-P-O-T-A-M-U-S = 12 letters) has a longer name than Elephant.
(a) Identifying Captains:
• Elephant: E-L-E-P-H-A-N-T = 8 letters (Longest)
• Ox: O-X = 2 letters (Shortest)
• Team 1 Captain: Elephant (8 letters)
• Team 2 Captain: Ox (2 letters)
(b) Animal with Longer Name:
• Yes! Crocodile (C-R-O-C-O-D-I-L-E = 9 letters) or Hippopotamus (H-I-P-P-O-P-O-T-A-M-U-S = 12 letters) has a longer name than Elephant.
CBSE Step-by-Step Marking Scheme
Correct identification of Elephant and Ox as captains
1.5 M
Valid example of animal with >8 letters (e.g., Crocodile/Hippopotamus)
1.5 M
Q5
Textbook Discussion • Comparing Names
Mahesh and Kartik are comparing the number of letters in their names.
(a) Count the letters in 'Mahesh' and 'Kartik'.
(b) Who has a longer name, or are they equal?
(c) If their friend 'Venkatanarasimha' joins them, how many more letters does this name have than Mahesh?
[3 Marks]
(a) Count the letters in 'Mahesh' and 'Kartik'.
(b) Who has a longer name, or are they equal?
(c) If their friend 'Venkatanarasimha' joins them, how many more letters does this name have than Mahesh?
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
(a) Counting Letters:
• M-A-H-E-S-H = 6 letters
• K-A-R-T-I-K = 6 letters
(b) Comparison:
• Both names have exactly 6 letters. Neither is longer; they are equal in length.
(c) Extra Letters:
• V-E-N-K-A-T-A-N-A-R-A-S-I-M-H-A = 16 letters.
• Difference = 16 - 6 = 10 more letters.
(a) Counting Letters:
• M-A-H-E-S-H = 6 letters
• K-A-R-T-I-K = 6 letters
(b) Comparison:
• Both names have exactly 6 letters. Neither is longer; they are equal in length.
(c) Extra Letters:
• V-E-N-K-A-T-A-N-A-R-A-S-I-M-H-A = 16 letters.
• Difference = 16 - 6 = 10 more letters.
CBSE Step-by-Step Marking Scheme
Correct counts for Mahesh (6) and Kartik (6)
1.0 M
Correct equality conclusion
1.0 M
Correct difference calculation (16 - 6 = 10)
1.0 M
Q6
Tally Marks & Herding • Goat & Sheep Counting
Ankit has 35 goats and Tanya has 27 goats.
(a) How many more goats does Ankit have than Tanya?
(b) Show Tanya's goat count (27) using tally marks in standard bundles of 5.
(c) If their flock also includes 14 black sheep and 19 white sheep, what is the total number of sheep?
[3 Marks]
(a) How many more goats does Ankit have than Tanya?
(b) Show Tanya's goat count (27) using tally marks in standard bundles of 5.
(c) If their flock also includes 14 black sheep and 19 white sheep, what is the total number of sheep?
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
(a) Difference in Goats:
• Ankit's goats = 35
• Tanya's goats = 27
• Difference = 35 - 27 = 8 more goats.
(b) Tally Marks for 27:
• 27 = (5 × 5) + 2 =|||| |||| |||| |||| |||| || (5 bundles of five plus 2 individual marks).
(c) Total Sheep:
• Black sheep = 14
• White sheep = 19
• Total sheep = 14 + 19 = 33 sheep.
(a) Difference in Goats:
• Ankit's goats = 35
• Tanya's goats = 27
• Difference = 35 - 27 = 8 more goats.
(b) Tally Marks for 27:
• 27 = (5 × 5) + 2 =
(c) Total Sheep:
• Black sheep = 14
• White sheep = 19
• Total sheep = 14 + 19 = 33 sheep.
CBSE Step-by-Step Marking Scheme
Correct subtraction (35 - 27 = 8)
1.0 M
Accurate tally mark representation (5 bundles + 2 lines)
1.0 M
Correct addition of sheep (14 + 19 = 33)
1.0 M
Q7
Number Names Mountain Climb • Spelling Length
In the number climb from 1 to 99, count the letters in the spelling of each number name (do not count hyphens):
(a) 'Seventy-eight'
(b) 'Ninety-three'
(c) 'Twenty-two'
Which of these three has the maximum number of letters, and which has the minimum?
[3 Marks]
(a) 'Seventy-eight'
(b) 'Ninety-three'
(c) 'Twenty-two'
Which of these three has the maximum number of letters, and which has the minimum?
✅ Step-by-Step Solution & Working
Letter Counting:
• (a) Seventy-eight: S-E-V-E-N-T-Y (7) + E-I-G-H-T (5) = 12 letters.
• (b) Ninety-three: N-I-N-E-T-Y (6) + T-H-R-E-E (5) = 11 letters.
• (c) Twenty-two: T-W-E-N-T-Y (6) + T-W-O (3) = 9 letters.
Conclusion:
• Maximum letters: Seventy-eight (12 letters)
• Minimum letters: Twenty-two (9 letters).
• (a) Seventy-eight: S-E-V-E-N-T-Y (7) + E-I-G-H-T (5) = 12 letters.
• (b) Ninety-three: N-I-N-E-T-Y (6) + T-H-R-E-E (5) = 11 letters.
• (c) Twenty-two: T-W-E-N-T-Y (6) + T-W-O (3) = 9 letters.
Conclusion:
• Maximum letters: Seventy-eight (12 letters)
• Minimum letters: Twenty-two (9 letters).
CBSE Step-by-Step Marking Scheme
Accurate letter count for all three number names (12, 11, 9)
1.5 M
Correct identification of maximum (78) and minimum (22)
1.5 M
Q8
Textbook Exercise • Name Length Comparison
In an animal team game, the following animal names are listed: Elephant, Ox, Deer, Kangaroo, Lion, Fox.
(a) Count the letters in each animal's name.
(b) Which animal has the longest name and which has the shortest?
(c) How many letters longer is the longest name compared to the shortest?
[3 Marks]
(a) Count the letters in each animal's name.
(b) Which animal has the longest name and which has the shortest?
(c) How many letters longer is the longest name compared to the shortest?
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
(a) Counting Letters:
• Elephant: E-L-E-P-H-A-N-T = 8 letters
• Ox: O-X = 2 letters
• Deer: D-E-E-R = 4 letters
• Kangaroo: K-A-N-G-A-R-O-O = 8 letters
• Lion: L-I-O-N = 4 letters
• Fox: F-O-X = 3 letters
(b) Longest & Shortest:
• Longest: Elephant and Kangaroo (8 letters each).
• Shortest: Ox (2 letters).
(c) Difference:
• 8 - 2 = 6 letters longer.
(a) Counting Letters:
• Elephant: E-L-E-P-H-A-N-T = 8 letters
• Ox: O-X = 2 letters
• Deer: D-E-E-R = 4 letters
• Kangaroo: K-A-N-G-A-R-O-O = 8 letters
• Lion: L-I-O-N = 4 letters
• Fox: F-O-X = 3 letters
(b) Longest & Shortest:
• Longest: Elephant and Kangaroo (8 letters each).
• Shortest: Ox (2 letters).
(c) Difference:
• 8 - 2 = 6 letters longer.
CBSE Step-by-Step Marking Scheme
Correct letter counts for all 6 animals
1.0 M
Correct longest and shortest identified
1.0 M
Difference calculation: 8 - 2 = 6
1.0 M
Q9
Textbook Activity • Starting Letter Frequency
In a class of 24 children, the teacher records their names: 6 start with 'S', 5 start with 'A', 4 start with 'M', 3 start with 'R', and 6 start with other letters.
(a) Which letter is the most common starting letter?
(b) How many names start with either 'S' or 'A'?
(c) Represent the counts for 'S', 'A', 'M', and 'R' using tally marks in bundles of 5.
[3 Marks]
(a) Which letter is the most common starting letter?
(b) How many names start with either 'S' or 'A'?
(c) Represent the counts for 'S', 'A', 'M', and 'R' using tally marks in bundles of 5.
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
• (a) Most common starting letter: Letter 'S' with 6 children.
• (b) Starting with 'S' or 'A': 6 + 5 = 11 names.
• (c) Tally marks:
• 'S' (6) =|||| |
• 'A' (5) =||||
• 'M' (4) = ||||
• 'R' (3) = |||.
• (a) Most common starting letter: Letter 'S' with 6 children.
• (b) Starting with 'S' or 'A': 6 + 5 = 11 names.
• (c) Tally marks:
• 'S' (6) =
• 'A' (5) =
• 'M' (4) = ||||
• 'R' (3) = |||.
CBSE Step-by-Step Marking Scheme
Most common starting letter 'S'
1.0 M
Sum of S and A = 11
1.0 M
Correct tally marks for all 4 categories
1.0 M
Q10
Textbook Exploration • Vowels in Names
Look at the name 'AMITABH':
(a) How many total letters are in this name?
(b) How many vowels (A, E, I, O, U) are present?
(c) How many consonants are present?
(d) What fraction of the letters are vowels?
[3 Marks]
(a) How many total letters are in this name?
(b) How many vowels (A, E, I, O, U) are present?
(c) How many consonants are present?
(d) What fraction of the letters are vowels?
✅ Step-by-Step Solution & Working
Analysis of 'AMITABH':
• Letters: A - M - I - T - A - B - H.
• (a) Total letters: 7 letters.
• (b) Vowels: A, I, A = 3 vowels.
• (c) Consonants: M, T, B, H = 4 consonants.
• (d) Fraction of vowels: 3 out of 7 = 3/7.
• Letters: A - M - I - T - A - B - H.
• (a) Total letters: 7 letters.
• (b) Vowels: A, I, A = 3 vowels.
• (c) Consonants: M, T, B, H = 4 consonants.
• (d) Fraction of vowels: 3 out of 7 = 3/7.
CBSE Step-by-Step Marking Scheme
Total letters = 7
0.5 M
Vowels = 3, Consonants = 4
1.5 M
Fraction = 3/7
1.0 M
Q11
Practice Time • Reversing Names
Some words read the same forward and backward, such as 'NOON' or 'RADAR'.
(a) Check if the names 'KANAK' and 'NAMAN' read the same backwards.
(b) Write down the letters of 'ROHIT' in reverse order. Does it form the same word?
[3 Marks]
(a) Check if the names 'KANAK' and 'NAMAN' read the same backwards.
(b) Write down the letters of 'ROHIT' in reverse order. Does it form the same word?
✅ Step-by-Step Solution & Working
Palindrome Word Analysis:
• (a) Checking KANAK & NAMAN:
• K-A-N-A-K reversed is K-A-N-A-K (Same!).
• N-A-M-A-N reversed is N-A-M-A-N (Same!).
Both are palindromes.
• (b) Reversing 'ROHIT':
• R-O-H-I-T in reverse order is T-I-H-O-R.
This is not the same word.
• (a) Checking KANAK & NAMAN:
• K-A-N-A-K reversed is K-A-N-A-K (Same!).
• N-A-M-A-N reversed is N-A-M-A-N (Same!).
Both are palindromes.
• (b) Reversing 'ROHIT':
• R-O-H-I-T in reverse order is T-I-H-O-R.
This is not the same word.
CBSE Step-by-Step Marking Scheme
Correct verification of KANAK and NAMAN as palindromes
1.5 M
Reversing ROHIT to TIHOR and concluding not the same
1.5 M
Q12
Let us Do • Name Length Ordering
Arrange the following names from shortest to longest (ascending order): Sunita (6), Ali (3), Dharmendra (10), Priya (5), Raj (3), Meenakshi (9).
[2 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Ordering:
1. Count each name:
• Ali: 3 letters
• Raj: 3 letters
• Priya: 5 letters
• Sunita: 6 letters
• Meenakshi: 9 letters
• Dharmendra: 10 letters
Ascending Order:
Ali / Raj (3) → Priya (5) → Sunita (6) → Meenakshi (9) → Dharmendra (10).
1. Count each name:
• Ali: 3 letters
• Raj: 3 letters
• Priya: 5 letters
• Sunita: 6 letters
• Meenakshi: 9 letters
• Dharmendra: 10 letters
Ascending Order:
Ali / Raj (3) → Priya (5) → Sunita (6) → Meenakshi (9) → Dharmendra (10).
CBSE Step-by-Step Marking Scheme
Correct counts for all names
1.0 M
Accurate ascending order
1.0 M
Q13
Classroom Project • Grouping by Letter Count
In a class, the teacher asked children with 4-letter names to stand in Line 1, 5-letter names in Line 2, and 6-letter names in Line 3. If there are 8 children in Line 1, 12 in Line 2, and 7 in Line 3:
(a) Which line has the largest number of children?
(b) How many children are there in all three lines combined?
[2 Marks]
(a) Which line has the largest number of children?
(b) How many children are there in all three lines combined?
✅ Step-by-Step Solution & Working
Calculations:
• (a) Line with most children: Line 2 (5-letter names) with 12 children.
• (b) Total children: 8 + 12 + 7 = 27 children.
• (a) Line with most children: Line 2 (5-letter names) with 12 children.
• (b) Total children: 8 + 12 + 7 = 27 children.
CBSE Step-by-Step Marking Scheme
Line 2 identified as largest (12 children)
1.0 M
Total count 8 + 12 + 7 = 27
1.0 M
Q14
Mental Math • Letter Arithmetic
If each letter in a name is worth 2 points, find the total points for the name 'KAVITA'. If 'DEEPAK' is scored the same way, who gets more points and by how much?
[2 Marks]
✅ Step-by-Step Solution & Working
Point Calculations:
• KAVITA has 6 letters: Score = 6 × 2 = 12 points.
• DEEPAK has 6 letters: Score = 6 × 2 = 12 points.
• Comparison: Both names have 6 letters, so both score exactly 12 points. Neither scores more; their points are equal.
• KAVITA has 6 letters: Score = 6 × 2 = 12 points.
• DEEPAK has 6 letters: Score = 6 × 2 = 12 points.
• Comparison: Both names have 6 letters, so both score exactly 12 points. Neither scores more; their points are equal.
CBSE Step-by-Step Marking Scheme
Kavita = 12 points, Deepak = 12 points
1.0 M
Conclusion of equal score
1.0 M
Q15
In-Text Exploration • Words with Common Letters
Find three 4-letter words that end with the letters 'O-O-K'. Write their names and count total letters.
[2 Marks]
✅ Step-by-Step Solution & Working
Words Ending in 'O-O-K':
1. BOOK (B-O-O-K = 4 letters)
2. LOOK (L-O-O-K = 4 letters)
3. COOK (C-O-O-K = 4 letters)
Other valid words: HOOK, TOOK.
Total letters across all three words = 4 + 4 + 4 = 12 letters.
1. BOOK (B-O-O-K = 4 letters)
2. LOOK (L-O-O-K = 4 letters)
3. COOK (C-O-O-K = 4 letters)
Other valid words: HOOK, TOOK.
Total letters across all three words = 4 + 4 + 4 = 12 letters.
CBSE Step-by-Step Marking Scheme
Three valid words ending in -ook
1.5 M
Total count = 12 letters
0.5 M
Q16
Critical Thinking • Name Code Puzzle
In a secret alphabet code, A=1, B=2, C=3, D=4, E=5. What is the sum of the letter values for the word 'B E D'?
[2 Marks]
✅ Step-by-Step Solution & Working
Code Calculation:
• B = 2
• E = 5
• D = 4
• Sum = 2 + 5 + 4 = 11.
The secret number code for 'BED' is 11.
• B = 2
• E = 5
• D = 4
• Sum = 2 + 5 + 4 = 11.
The secret number code for 'BED' is 11.
CBSE Step-by-Step Marking Scheme
Correct code values B=2, E=5, D=4
1.0 M
Sum = 11
1.0 M
Q17
Textbook Discussion • Family Name Comparison
Ritu's family has 4 members: Father (Ramesh - 6 letters), Mother (Sunita - 6 letters), Brother (Aman - 4 letters), and Ritu (4 letters).
(a) What is the total number of letters in all 4 names?
(b) What is the average number of letters per person?
[2 Marks]
(a) What is the total number of letters in all 4 names?
(b) What is the average number of letters per person?
✅ Step-by-Step Solution & Working
Calculations:
• (a) Total Letters: 6 + 6 + 4 + 4 = 20 letters.
• (b) Average: Total letters ÷ 4 members = 20 ÷ 4 = 5 letters per person.
• (a) Total Letters: 6 + 6 + 4 + 4 = 20 letters.
• (b) Average: Total letters ÷ 4 members = 20 ÷ 4 = 5 letters per person.
CBSE Step-by-Step Marking Scheme
Total letters = 20
1.0 M
Average = 5 letters
1.0 M
Q18
Summary Practice • True or False
State whether each statement is True or False:
(a) The name 'AARAV' has more vowels than consonants.
(b) 'INDIA' has exactly 5 letters.
(c) A tally mark bundle of 5 is drawn as five vertical lines without any cross line.
[3 Marks]
(a) The name 'AARAV' has more vowels than consonants.
(b) 'INDIA' has exactly 5 letters.
(c) A tally mark bundle of 5 is drawn as five vertical lines without any cross line.
✅ Step-by-Step Solution & Working
Answers:
• (a) True: AARAV has 3 vowels (A, A, A) and 2 consonants (R, V). 3 > 2.
• (b) True: I-N-D-I-A has 5 letters.
• (c) False: In standard tally marks, a bundle of 5 is drawn as 4 vertical lines with the 5th line drawn diagonally across them (||||).
• (a) True: AARAV has 3 vowels (A, A, A) and 2 consonants (R, V). 3 > 2.
• (b) True: I-N-D-I-A has 5 letters.
• (c) False: In standard tally marks, a bundle of 5 is drawn as 4 vertical lines with the 5th line drawn diagonally across them (
CBSE Step-by-Step Marking Scheme
(a) True with explanation
1.0 M
(b) True
1.0 M
(c) False with explanation of diagonal slash
1.0 M
Q19
Textbook Exercise • Practical Problem Solving
In Chapter 1 ('What's in a Name?'), a student solves an exercise problem: If 1 packet contains 12 items, how many items are in 4 such packets? Explain using repeated addition and multiplication.
[2 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
1. Repeated addition: 12 + 12 + 12 + 12 = 48 items.
2. Multiplication fact: 4 × 12 = 48 items.
3. Both methods yield the exact same answer. Multiplication is efficient repeated addition.
1. Repeated addition: 12 + 12 + 12 + 12 = 48 items.
2. Multiplication fact: 4 × 12 = 48 items.
3. Both methods yield the exact same answer. Multiplication is efficient repeated addition.
CBSE Step-by-Step Marking Scheme
Repeated addition 12+12+12+12 = 48
1 M
Multiplication 4 × 12 = 48
1 M
Q20
In-Text Activity • Concept Exploration
In 'What's in a Name?', how do you verify your mathematical calculations? Give an example using two numbers that add up to 100.
[2 Marks]
✅ Step-by-Step Solution & Working
Verification Method:
• Take two numbers: 65 and 35. Sum = 65 + 35 = 100.
• Verification by inverse operation (subtraction): 100 - 35 = 65, and 100 - 65 = 35.
• Since subtraction brings back the original numbers, the addition is confirmed correct.
• Take two numbers: 65 and 35. Sum = 65 + 35 = 100.
• Verification by inverse operation (subtraction): 100 - 35 = 65, and 100 - 65 = 35.
• Since subtraction brings back the original numbers, the addition is confirmed correct.
CBSE Step-by-Step Marking Scheme
Addition 65 + 35 = 100
1 M
Inverse check 100 - 35 = 65
1 M
Q21
Practice Time • Mental Math Drills
Solve mentally:
(a) 25 + 75 = ?
(b) 150 - 60 = ?
(c) Double of 45 = ?
(d) Half of 80 = ?
[2 Marks]
(a) 25 + 75 = ?
(b) 150 - 60 = ?
(c) Double of 45 = ?
(d) Half of 80 = ?
✅ Step-by-Step Solution & Working
Mental Calculations:
• (a) 25 + 75 = 100.
• (b) 150 - 60 = 90.
• (c) 45 × 2 = 90.
• (d) 80 ÷ 2 = 40.
• (a) 25 + 75 = 100.
• (b) 150 - 60 = 90.
• (c) 45 × 2 = 90.
• (d) 80 ÷ 2 = 40.
CBSE Step-by-Step Marking Scheme
All 4 mental math facts correct
2 M
Q22
Word Problem • Real Life Application
A school library received 3 boxes of mathematics activity books. Each box contained 25 books. During the week, 38 books were distributed to Grade 3 children. How many books remain in the library?
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
1. Total books received = 3 × 25 = 75 books.
2. Books distributed = 38 books.
3. Books remaining = 75 - 38 = 37 books.
1. Total books received = 3 × 25 = 75 books.
2. Books distributed = 38 books.
3. Books remaining = 75 - 38 = 37 books.
CBSE Step-by-Step Marking Scheme
Total 3 × 25 = 75
1.5 M
Remainder 75 - 38 = 37
1.5 M
Q23
Critical Thinking • Finding the Pattern
Observe the sequence related to 'What's in a Name?': 12, 24, 36, 48, ___, ___. Find the next two terms and state the mathematical rule.
[2 Marks]
✅ Step-by-Step Solution & Working
Pattern Analysis:
• 12 + 12 = 24
• 24 + 12 = 36
• 36 + 12 = 48
• Rule: Successive addition of 12 (Multiples of 12).
• Next terms: 48 + 12 = 60, 60 + 12 = 72.
• 12 + 12 = 24
• 24 + 12 = 36
• 36 + 12 = 48
• Rule: Successive addition of 12 (Multiples of 12).
• Next terms: 48 + 12 = 60, 60 + 12 = 72.
CBSE Step-by-Step Marking Scheme
Next terms 60, 72
1 M
Rule: multiples of 12 / +12 step
1 M
Q24
Estimation & Measurement • Practical Judgment
Estimate whether each measurement is greater than or less than 1 metre:
(a) Length of your classroom pencil.
(b) Height of your classroom teacher.
(c) Width of your mathematics textbook.
(d) Length of the school blackboard.
[2 Marks]
(a) Length of your classroom pencil.
(b) Height of your classroom teacher.
(c) Width of your mathematics textbook.
(d) Length of the school blackboard.
✅ Step-by-Step Solution & Working
Estimation:
• (a) Pencil: Less than 1 metre (approx. 15 cm).
• (b) Teacher height: Greater than 1 metre (approx. 1.6 to 1.7 m).
• (c) Textbook width: Less than 1 metre (approx. 20 cm).
• (d) Blackboard length: Greater than 1 metre (approx. 2 to 3 m).
• (a) Pencil: Less than 1 metre (approx. 15 cm).
• (b) Teacher height: Greater than 1 metre (approx. 1.6 to 1.7 m).
• (c) Textbook width: Less than 1 metre (approx. 20 cm).
• (d) Blackboard length: Greater than 1 metre (approx. 2 to 3 m).
CBSE Step-by-Step Marking Scheme
Correct estimation for all 4 items
2 M
Q25
Data Interpretation • Reading Simple Tables
A table shows student preferences for fruit: Apple (15), Banana (22), Mango (35), Orange (18).
(a) Which fruit is preferred by the maximum number of students?
(b) How many more students prefer Mango over Banana?
(c) What is the total number of students surveyed?
[3 Marks]
(a) Which fruit is preferred by the maximum number of students?
(b) How many more students prefer Mango over Banana?
(c) What is the total number of students surveyed?
✅ Step-by-Step Solution & Working
Table Interpretation:
• (a) Maximum preference: Mango with 35 students.
• (b) Difference: 35 - 22 = 13 more students prefer Mango.
• (c) Total students: 15 + 22 + 35 + 18 = 90 students.
• (a) Maximum preference: Mango with 35 students.
• (b) Difference: 35 - 22 = 13 more students prefer Mango.
• (c) Total students: 15 + 22 + 35 + 18 = 90 students.
CBSE Step-by-Step Marking Scheme
Mango identified
1 M
Difference = 13
1 M
Total = 90
1 M
Q26
Let us Do • Shapes and Symmetry
Draw a line of symmetry through each shape:
(a) A rectangle
(b) An equilateral triangle
(c) A circle.
How many lines of symmetry does a circle have?
[3 Marks]
(a) A rectangle
(b) An equilateral triangle
(c) A circle.
How many lines of symmetry does a circle have?
✅ Step-by-Step Solution & Working
Symmetry Properties:
• (a) A rectangle has 2 lines of symmetry (horizontal and vertical through centers of opposite sides).
• (b) An equilateral triangle has 3 lines of symmetry (from each vertex to opposite midpoint).
• (c) A circle has infinite lines of symmetry (any diameter passing through the center).
• (a) A rectangle has 2 lines of symmetry (horizontal and vertical through centers of opposite sides).
• (b) An equilateral triangle has 3 lines of symmetry (from each vertex to opposite midpoint).
• (c) A circle has infinite lines of symmetry (any diameter passing through the center).
CBSE Step-by-Step Marking Scheme
Rectangle = 2 lines
1 M
Triangle = 3 lines
1 M
Circle = infinite lines
1 M
Q27
Puzzle Time • Missing Number Grid
In a 3x3 magic square, the sum of each row, column, and diagonal is 15. The center number is 5. What numbers go in the opposite corners if one corner is 2?
[2 Marks]
✅ Step-by-Step Solution & Working
Magic Square Logic:
• In a 3x3 magic square with sum 15 and center 5, opposite corners must sum to 10 (since 2 + 5 + x = 15 → x = 8).
• If one corner is 2, the diagonally opposite corner must be 8.
• Other corner pairs: 4 and 6.
• In a 3x3 magic square with sum 15 and center 5, opposite corners must sum to 10 (since 2 + 5 + x = 15 → x = 8).
• If one corner is 2, the diagonally opposite corner must be 8.
• Other corner pairs: 4 and 6.
CBSE Step-by-Step Marking Scheme
Opposite corner = 8 with reasoning
2 M
Q28
Money & Shopping • Cash Memo Bill
Rani visits a stationery shop and buys: 2 Pencils at ₹5 each, 1 Eraser for ₹3, and 1 Notebook for ₹25. Prepare a simple cash memo showing total bill and change returned from a ₹50 note.
[3 Marks]
✅ Step-by-Step Solution & Working
Cash Memo Preparation:
• 2 Pencils @ ₹5 = ₹10
• 1 Eraser @ ₹3 = ₹3
• 1 Notebook @ ₹25 = ₹25
• Total Bill Amount = ₹10 + ₹3 + ₹25 = ₹38.
• Amount paid = ₹50.
• Change returned = ₹50 - ₹38 = ₹12.
• 2 Pencils @ ₹5 = ₹10
• 1 Eraser @ ₹3 = ₹3
• 1 Notebook @ ₹25 = ₹25
• Total Bill Amount = ₹10 + ₹3 + ₹25 = ₹38.
• Amount paid = ₹50.
• Change returned = ₹50 - ₹38 = ₹12.
CBSE Step-by-Step Marking Scheme
Correct item breakdown and total ₹38
2 M
Change = ₹12
1 M
Q29
Chapter Review • Comprehensive Concept Check
True or False:
(a) 1 kilometre is equal to 1000 metres.
(b) 500 millilitres is equal to half a litre.
(c) A square has 4 equal straight edges and 4 right-angled corners.
[3 Marks]
(a) 1 kilometre is equal to 1000 metres.
(b) 500 millilitres is equal to half a litre.
(c) A square has 4 equal straight edges and 4 right-angled corners.
✅ Step-by-Step Solution & Working
Review Answers:
• (a) True: 1 km = 1000 m.
• (b) True: 1 Litre = 1000 mL, so half a litre = 500 mL.
• (c) True: A square has 4 equal sides and 4 right angles.
• (a) True: 1 km = 1000 m.
• (b) True: 1 Litre = 1000 mL, so half a litre = 500 mL.
• (c) True: A square has 4 equal sides and 4 right angles.
CBSE Step-by-Step Marking Scheme
All 3 statements correctly evaluated as True
3 M
🌟 NEP 2020 Competency-Based Case Study
Library Badge Code Challenge
The school librarian gives each child a library code based on their name: 10 points for each letter in the first name plus 5 points for each vowel (A, E, I, O, U).
Analytical Task: Calculate the total library badge score for 'KAVITA'. How many vowels are in her name, and what is her final code value?
Evaluation & Model Answer:
1. Name: K-A-V-I-T-A contains 6 letters.
2. Letter points = 6 × 10 = 60 points.
3. Vowels in KAVITA: A, I, A = 3 vowels.
4. Vowel bonus points = 3 × 5 = 15 points.
5. Total library badge score = 60 + 15 = 75 points.
2. Letter points = 6 × 10 = 60 points.
3. Vowels in KAVITA: A, I, A = 3 vowels.
4. Vowel bonus points = 3 × 5 = 15 points.
5. Total library badge score = 60 + 15 = 75 points.
Rubric: 1M letter points + 1M vowel identification + 1M final calculation.