Chapter 10 of 14
Chapter 10: Fun at Class Party!
Repeated Addition, Arrays, Multiplication Tables (2, 3, 4, 5, 10) & Party Budgets | CBSE Session 2026–27
Core Pedagogical Competencies & Concepts
- Multiplication as repeated addition of equal groups.
- Arranging objects in rows and columns: understanding arrays (e.g., 4 rows of 5).
- Building multiplication tables for 2, 3, 4, 5, and 10 using patterns.
- Calculating costs for party food items using unit rates.
All Textbook Exercises & In-Text Tasks (18 Questions)
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Q1
Array Model • Multiplication Sentence
In the classroom party, chairs are placed in 5 rows with 8 chairs in each row. (a) Write the repeated addition fact. (b) Write the multiplication fact. (c) How many total chairs are there?
[3 Marks]
✅ Step-by-Step Solution & Working
Solution:
• Number of rows = 5
• Chairs in each row = 8
(a) Repeated Addition: 8 + 8 + 8 + 8 + 8 = 40.
(b) Multiplication Fact: 5 × 8 = 40.
(c) Total Chairs: 40 chairs.
• Number of rows = 5
• Chairs in each row = 8
(a) Repeated Addition: 8 + 8 + 8 + 8 + 8 = 40.
(b) Multiplication Fact: 5 × 8 = 40.
(c) Total Chairs: 40 chairs.
CBSE Step-by-Step Marking Scheme
Correct repeated addition statement
1.0 M
Correct multiplication statement
1.0 M
Correct total chair count
1.0 M
Q2
Multiplication Tables • Patterns
Look at the 5 times table: 5, 10, 15, 20, 25, 30... (a) What pattern do you notice in the ones digit? (b) Can any number ending in 7 be in the 5 times table? Why or why not?
[2 Marks]
✅ Step-by-Step Solution & Working
Analysis:
(a) Ones Digit Pattern: The ones digit alternates continuously between 5 and 0.
(b) Ending in 7: No, because every multiple of 5 must end in either 0 or 5. A number ending in 7 will always leave a remainder of 2 when divided by 5.
(a) Ones Digit Pattern: The ones digit alternates continuously between 5 and 0.
(b) Ending in 7: No, because every multiple of 5 must end in either 0 or 5. A number ending in 7 will always leave a remainder of 2 when divided by 5.
CBSE Step-by-Step Marking Scheme
Identification of alternating 5 and 0 pattern
1.0 M
Correct justification regarding remainder 2
1.0 M
Q3
Unit Costing • Real-Life Math
For a class party, the teacher bought: 6 packs of juice at ₹10 each, 4 packets of paper cups at ₹15 each, and 5 bags of popcorn at ₹20 each. Calculate the total expenditure.
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-step Calculation:
1. Cost of juice = 6 × ₹10 = ₹60
2. Cost of paper cups = 4 × ₹15 = ₹60
3. Cost of popcorn = 5 × ₹20 = ₹100
4. Total Expenditure = ₹60 + ₹60 + ₹100 = ₹220.
1. Cost of juice = 6 × ₹10 = ₹60
2. Cost of paper cups = 4 × ₹15 = ₹60
3. Cost of popcorn = 5 × ₹20 = ₹100
4. Total Expenditure = ₹60 + ₹60 + ₹100 = ₹220.
CBSE Step-by-Step Marking Scheme
Correct multiplication for each item type
1.5 M
Correct summation of total bill (₹220)
1.5 M
Q4
Drink Sharing • Capacity Math
For the class party, the teacher bought two 2-litre bottles of mango juice.
(a) How many total litres of mango juice were bought?
(b) Convert the total litres into millilitres (mL).
(c) If each paper cup holds 200 mL, how many cups of juice can be served in total?
[3 Marks]
(a) How many total litres of mango juice were bought?
(b) Convert the total litres into millilitres (mL).
(c) If each paper cup holds 200 mL, how many cups of juice can be served in total?
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
(a) Total Litres:
• 2 bottles × 2 litres = 4 litres.
(b) Conversion to mL:
• 1 litre = 1000 mL.
• 4 litres = 4 × 1000 = 4000 mL.
(c) Cups Served:
• Capacity per cup = 200 mL.
• Total cups = 4000 ÷ 200 = 20 cups.
(a) Total Litres:
• 2 bottles × 2 litres = 4 litres.
(b) Conversion to mL:
• 1 litre = 1000 mL.
• 4 litres = 4 × 1000 = 4000 mL.
(c) Cups Served:
• Capacity per cup = 200 mL.
• Total cups = 4000 ÷ 200 = 20 cups.
CBSE Step-by-Step Marking Scheme
Correct total litres (4 L)
1.0 M
Correct conversion (4000 mL)
1.0 M
Correct cups division (20 cups)
1.0 M
Q5
Party Schedule • Duration Calculation
The Class 3 party began at 10:45 AM and ended at 1:15 PM.
(a) How many hours and minutes did the party last?
(b) If musical chairs took 40 minutes and quiz took 30 minutes, how much time was left for eating snacks and dancing?
[3 Marks]
(a) How many hours and minutes did the party last?
(b) If musical chairs took 40 minutes and quiz took 30 minutes, how much time was left for eating snacks and dancing?
✅ Step-by-Step Solution & Working
Step-by-Step Time Calculation:
(a) Total Duration:
• From 10:45 AM to 11:00 AM = 15 minutes.
• From 11:00 AM to 1:00 PM = 2 hours.
• From 1:00 PM to 1:15 PM = 15 minutes.
• Total = 2 hours + 15 min + 15 min = 2 hours 30 minutes (or 150 minutes).
(b) Remaining Time:
• Games time = 40 min + 30 min = 70 minutes.
• Remaining time = 150 min - 70 min = 80 minutes (or 1 hour 20 minutes).
(a) Total Duration:
• From 10:45 AM to 11:00 AM = 15 minutes.
• From 11:00 AM to 1:00 PM = 2 hours.
• From 1:00 PM to 1:15 PM = 15 minutes.
• Total = 2 hours + 15 min + 15 min = 2 hours 30 minutes (or 150 minutes).
(b) Remaining Time:
• Games time = 40 min + 30 min = 70 minutes.
• Remaining time = 150 min - 70 min = 80 minutes (or 1 hour 20 minutes).
CBSE Step-by-Step Marking Scheme
Correct total duration (2 hours 30 minutes)
1.5 M
Correct remaining time (80 minutes / 1 hr 20 min)
1.5 M
Q6
Snack Budget & Cash Memo
Prepare a bill for the following party purchases:
• 25 samosas at ₹8 each
• 30 bananas at ₹4 each
• 2 packets of paper plates at ₹25 per packet
Calculate the total bill and the change from a ₹500 note.
[3 Marks]
• 25 samosas at ₹8 each
• 30 bananas at ₹4 each
• 2 packets of paper plates at ₹25 per packet
Calculate the total bill and the change from a ₹500 note.
✅ Step-by-Step Solution & Working
Step-by-Step Bill:
• Samosas: 25 × ₹8 = ₹200.
• Bananas: 30 × ₹4 = ₹120.
• Plates: 2 × ₹25 = ₹50.
• Total Bill: ₹200 + ₹120 + ₹50 = ₹370.
Change from ₹500:
• Change = ₹500 - ₹370 = ₹130.
• Samosas: 25 × ₹8 = ₹200.
• Bananas: 30 × ₹4 = ₹120.
• Plates: 2 × ₹25 = ₹50.
• Total Bill: ₹200 + ₹120 + ₹50 = ₹370.
Change from ₹500:
• Change = ₹500 - ₹370 = ₹130.
CBSE Step-by-Step Marking Scheme
Correct itemised multiplication and sum (₹370)
2.0 M
Correct change subtraction (₹130)
1.0 M
Q7
Tally Chart of Party Games
In a survey of 24 children about their favorite party game:
• 8 chose Musical Chairs
• 7 chose Dumb Charades
• 5 chose Antakshari
• 4 chose Passing the Parcel
(a) Draw a tally chart representing these votes.
(b) Which game was the most popular and which was the least popular?
[3 Marks]
• 8 chose Musical Chairs
• 7 chose Dumb Charades
• 5 chose Antakshari
• 4 chose Passing the Parcel
(a) Draw a tally chart representing these votes.
(b) Which game was the most popular and which was the least popular?
✅ Step-by-Step Solution & Working
(a) Tally Chart:
(b) Popularity:
• Most popular: Musical Chairs (8 votes).
• Least popular: Passing the Parcel (4 votes).
| Game | Tally Marks | Number of Votes |
|---|---|---|
| Musical Chairs | 8 | |
| Dumb Charades | 7 | |
| Antakshari | 5 | |
| Passing the Parcel | |||| | 4 |
| Total | — | 24 |
(b) Popularity:
• Most popular: Musical Chairs (8 votes).
• Least popular: Passing the Parcel (4 votes).
CBSE Step-by-Step Marking Scheme
Correct tally marks layout and bundle counts
2.0 M
Correct identification of most and least popular games
1.0 M
Q8
Textbook Exercise • Practical Problem Solving
In Chapter 10 ('Fun at Class Party!'), a student solves an exercise problem: If 1 packet contains 12 items, how many items are in 4 such packets? Explain using repeated addition and multiplication.
[2 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
1. Repeated addition: 12 + 12 + 12 + 12 = 48 items.
2. Multiplication fact: 4 × 12 = 48 items.
3. Both methods yield the exact same answer. Multiplication is efficient repeated addition.
1. Repeated addition: 12 + 12 + 12 + 12 = 48 items.
2. Multiplication fact: 4 × 12 = 48 items.
3. Both methods yield the exact same answer. Multiplication is efficient repeated addition.
CBSE Step-by-Step Marking Scheme
Repeated addition 12+12+12+12 = 48
1 M
Multiplication 4 × 12 = 48
1 M
Q9
In-Text Activity • Concept Exploration
In 'Fun at Class Party!', how do you verify your mathematical calculations? Give an example using two numbers that add up to 100.
[2 Marks]
✅ Step-by-Step Solution & Working
Verification Method:
• Take two numbers: 65 and 35. Sum = 65 + 35 = 100.
• Verification by inverse operation (subtraction): 100 - 35 = 65, and 100 - 65 = 35.
• Since subtraction brings back the original numbers, the addition is confirmed correct.
• Take two numbers: 65 and 35. Sum = 65 + 35 = 100.
• Verification by inverse operation (subtraction): 100 - 35 = 65, and 100 - 65 = 35.
• Since subtraction brings back the original numbers, the addition is confirmed correct.
CBSE Step-by-Step Marking Scheme
Addition 65 + 35 = 100
1 M
Inverse check 100 - 35 = 65
1 M
Q10
Practice Time • Mental Math Drills
Solve mentally:
(a) 25 + 75 = ?
(b) 150 - 60 = ?
(c) Double of 45 = ?
(d) Half of 80 = ?
[2 Marks]
(a) 25 + 75 = ?
(b) 150 - 60 = ?
(c) Double of 45 = ?
(d) Half of 80 = ?
✅ Step-by-Step Solution & Working
Mental Calculations:
• (a) 25 + 75 = 100.
• (b) 150 - 60 = 90.
• (c) 45 × 2 = 90.
• (d) 80 ÷ 2 = 40.
• (a) 25 + 75 = 100.
• (b) 150 - 60 = 90.
• (c) 45 × 2 = 90.
• (d) 80 ÷ 2 = 40.
CBSE Step-by-Step Marking Scheme
All 4 mental math facts correct
2 M
Q11
Word Problem • Real Life Application
A school library received 3 boxes of mathematics activity books. Each box contained 25 books. During the week, 38 books were distributed to Grade 3 children. How many books remain in the library?
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
1. Total books received = 3 × 25 = 75 books.
2. Books distributed = 38 books.
3. Books remaining = 75 - 38 = 37 books.
1. Total books received = 3 × 25 = 75 books.
2. Books distributed = 38 books.
3. Books remaining = 75 - 38 = 37 books.
CBSE Step-by-Step Marking Scheme
Total 3 × 25 = 75
1.5 M
Remainder 75 - 38 = 37
1.5 M
Q12
Critical Thinking • Finding the Pattern
Observe the sequence related to 'Fun at Class Party!': 12, 24, 36, 48, ___, ___. Find the next two terms and state the mathematical rule.
[2 Marks]
✅ Step-by-Step Solution & Working
Pattern Analysis:
• 12 + 12 = 24
• 24 + 12 = 36
• 36 + 12 = 48
• Rule: Successive addition of 12 (Multiples of 12).
• Next terms: 48 + 12 = 60, 60 + 12 = 72.
• 12 + 12 = 24
• 24 + 12 = 36
• 36 + 12 = 48
• Rule: Successive addition of 12 (Multiples of 12).
• Next terms: 48 + 12 = 60, 60 + 12 = 72.
CBSE Step-by-Step Marking Scheme
Next terms 60, 72
1 M
Rule: multiples of 12 / +12 step
1 M
Q13
Estimation & Measurement • Practical Judgment
Estimate whether each measurement is greater than or less than 1 metre:
(a) Length of your classroom pencil.
(b) Height of your classroom teacher.
(c) Width of your mathematics textbook.
(d) Length of the school blackboard.
[2 Marks]
(a) Length of your classroom pencil.
(b) Height of your classroom teacher.
(c) Width of your mathematics textbook.
(d) Length of the school blackboard.
✅ Step-by-Step Solution & Working
Estimation:
• (a) Pencil: Less than 1 metre (approx. 15 cm).
• (b) Teacher height: Greater than 1 metre (approx. 1.6 to 1.7 m).
• (c) Textbook width: Less than 1 metre (approx. 20 cm).
• (d) Blackboard length: Greater than 1 metre (approx. 2 to 3 m).
• (a) Pencil: Less than 1 metre (approx. 15 cm).
• (b) Teacher height: Greater than 1 metre (approx. 1.6 to 1.7 m).
• (c) Textbook width: Less than 1 metre (approx. 20 cm).
• (d) Blackboard length: Greater than 1 metre (approx. 2 to 3 m).
CBSE Step-by-Step Marking Scheme
Correct estimation for all 4 items
2 M
Q14
Data Interpretation • Reading Simple Tables
A table shows student preferences for fruit: Apple (15), Banana (22), Mango (35), Orange (18).
(a) Which fruit is preferred by the maximum number of students?
(b) How many more students prefer Mango over Banana?
(c) What is the total number of students surveyed?
[3 Marks]
(a) Which fruit is preferred by the maximum number of students?
(b) How many more students prefer Mango over Banana?
(c) What is the total number of students surveyed?
✅ Step-by-Step Solution & Working
Table Interpretation:
• (a) Maximum preference: Mango with 35 students.
• (b) Difference: 35 - 22 = 13 more students prefer Mango.
• (c) Total students: 15 + 22 + 35 + 18 = 90 students.
• (a) Maximum preference: Mango with 35 students.
• (b) Difference: 35 - 22 = 13 more students prefer Mango.
• (c) Total students: 15 + 22 + 35 + 18 = 90 students.
CBSE Step-by-Step Marking Scheme
Mango identified
1 M
Difference = 13
1 M
Total = 90
1 M
Q15
Let us Do • Shapes and Symmetry
Draw a line of symmetry through each shape:
(a) A rectangle
(b) An equilateral triangle
(c) A circle.
How many lines of symmetry does a circle have?
[3 Marks]
(a) A rectangle
(b) An equilateral triangle
(c) A circle.
How many lines of symmetry does a circle have?
✅ Step-by-Step Solution & Working
Symmetry Properties:
• (a) A rectangle has 2 lines of symmetry (horizontal and vertical through centers of opposite sides).
• (b) An equilateral triangle has 3 lines of symmetry (from each vertex to opposite midpoint).
• (c) A circle has infinite lines of symmetry (any diameter passing through the center).
• (a) A rectangle has 2 lines of symmetry (horizontal and vertical through centers of opposite sides).
• (b) An equilateral triangle has 3 lines of symmetry (from each vertex to opposite midpoint).
• (c) A circle has infinite lines of symmetry (any diameter passing through the center).
CBSE Step-by-Step Marking Scheme
Rectangle = 2 lines
1 M
Triangle = 3 lines
1 M
Circle = infinite lines
1 M
Q16
Puzzle Time • Missing Number Grid
In a 3x3 magic square, the sum of each row, column, and diagonal is 15. The center number is 5. What numbers go in the opposite corners if one corner is 2?
[2 Marks]
✅ Step-by-Step Solution & Working
Magic Square Logic:
• In a 3x3 magic square with sum 15 and center 5, opposite corners must sum to 10 (since 2 + 5 + x = 15 → x = 8).
• If one corner is 2, the diagonally opposite corner must be 8.
• Other corner pairs: 4 and 6.
• In a 3x3 magic square with sum 15 and center 5, opposite corners must sum to 10 (since 2 + 5 + x = 15 → x = 8).
• If one corner is 2, the diagonally opposite corner must be 8.
• Other corner pairs: 4 and 6.
CBSE Step-by-Step Marking Scheme
Opposite corner = 8 with reasoning
2 M
Q17
Money & Shopping • Cash Memo Bill
Rani visits a stationery shop and buys: 2 Pencils at ₹5 each, 1 Eraser for ₹3, and 1 Notebook for ₹25. Prepare a simple cash memo showing total bill and change returned from a ₹50 note.
[3 Marks]
✅ Step-by-Step Solution & Working
Cash Memo Preparation:
• 2 Pencils @ ₹5 = ₹10
• 1 Eraser @ ₹3 = ₹3
• 1 Notebook @ ₹25 = ₹25
• Total Bill Amount = ₹10 + ₹3 + ₹25 = ₹38.
• Amount paid = ₹50.
• Change returned = ₹50 - ₹38 = ₹12.
• 2 Pencils @ ₹5 = ₹10
• 1 Eraser @ ₹3 = ₹3
• 1 Notebook @ ₹25 = ₹25
• Total Bill Amount = ₹10 + ₹3 + ₹25 = ₹38.
• Amount paid = ₹50.
• Change returned = ₹50 - ₹38 = ₹12.
CBSE Step-by-Step Marking Scheme
Correct item breakdown and total ₹38
2 M
Change = ₹12
1 M
Q18
Chapter Review • Comprehensive Concept Check
True or False:
(a) 1 kilometre is equal to 1000 metres.
(b) 500 millilitres is equal to half a litre.
(c) A square has 4 equal straight edges and 4 right-angled corners.
[3 Marks]
(a) 1 kilometre is equal to 1000 metres.
(b) 500 millilitres is equal to half a litre.
(c) A square has 4 equal straight edges and 4 right-angled corners.
✅ Step-by-Step Solution & Working
Review Answers:
• (a) True: 1 km = 1000 m.
• (b) True: 1 Litre = 1000 mL, so half a litre = 500 mL.
• (c) True: A square has 4 equal sides and 4 right angles.
• (a) True: 1 km = 1000 m.
• (b) True: 1 Litre = 1000 mL, so half a litre = 500 mL.
• (c) True: A square has 4 equal sides and 4 right angles.
CBSE Step-by-Step Marking Scheme
All 3 statements correctly evaluated as True
3 M
🌟 NEP 2020 Competency-Based Case Study
Party Gift Return Bags
The class teacher prepares 25 return gift pouches for students. In each pouch, she places 3 crayons and 2 stickers.
Analytical Task: How many crayons and how many stickers will she need in total? What is the total count of all gift items?
Evaluation & Model Answer:
1. Total crayons needed = 25 × 3 = 75 crayons.
2. Total stickers needed = 25 × 2 = 50 stickers.
3. Total gift items = 75 + 50 = 125 items (or 25 × 5 = 125 items).
2. Total stickers needed = 25 × 2 = 50 stickers.
3. Total gift items = 75 + 50 = 125 items (or 25 × 5 = 125 items).
Rubric: 1M crayons multiplication + 1M stickers multiplication + 1M total sum.