Chapter 2 of 14
⬅️ Ch 1: What's in a Name? Ch 3: Double Century ➡️
NCERT Class 3 Mathematics • New NEP 2020 / NCF 2023

Chapter 2: Toy Joy

Counting, Grouping, Place Value (Tens & Ones) & Price Tag Calculations | CBSE Session 2026–27

Core Pedagogical Competencies & Concepts
  • Grouping objects in tens and ones: building base-10 understanding.
  • Forming 2-digit numbers using bundles of 10 sticks and loose 1s.
  • Reading price tags on toys and combining coins/notes to pay exact amounts.
  • Comparing toy prices: finding which costs more and which costs less.
Toy Joy — Tens & Ones Place Value Model 4 Tens = 40 + 6 Ones = 6 = 46 Toy Car Price: ₹46

All Textbook Exercises & In-Text Tasks (18 Questions)

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Q1 Textbook Exercise • Tens & Ones
A toy shop owner has 64 marbles. How many packets of 10 marbles can she make, and how many loose marbles will be left over? Write 64 in expanded form.
[2 Marks]
✅ Step-by-Step Solution & Working
Solution:
• Total marbles = 64
• Number of tens in 64 = 6 packets of 10 (6 × 10 = 60)
• Loose marbles left over = 4 marbles
• Expanded Form: 64 = 60 + 4 = 6 Tens + 4 Ones.
CBSE Step-by-Step Marking Scheme
Correct number of packets (6) and loose (4) 1.0 M
Correct expanded form representation (60 + 4) 1.0 M
Q2 Textbook Exercise • Money & Pricing
Rani buys a teddy bear for ₹38 and a spinning top for ₹24. (a) What is the total cost? (b) If she gives a ₹100 note to the shopkeeper, how much change should she receive?
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-step Solution:
(a) Total Cost:
Cost of teddy bear = ₹38
Cost of spinning top = ₹24
Total = ₹38 + ₹24 = ₹(30 + 20 + 8 + 4) = ₹50 + ₹12 = ₹62.

(b) Change Received:
Amount given = ₹100
Total spent = ₹62
Change = ₹100 - ₹62 = ₹38.
CBSE Step-by-Step Marking Scheme
Correct addition for total cost (₹62) 1.5 M
Correct subtraction for balance change (₹38) 1.5 M
Q3 Logical Puzzle • Number Riddle
I have 5 in my tens place. The digit in my ones place is 3 more than the digit in my tens place. What number am I? Is this number even or odd?
[2 Marks]
✅ Step-by-Step Solution & Working
Deduction:
1. Digit in tens place = 5
2. Digit in ones place = 5 + 3 = 8
3. The number is 58.
4. Since the ones digit is 8 (divisible by 2), the number 58 is an EVEN number.
CBSE Step-by-Step Marking Scheme
Correct calculation of ones digit and number 58 1.0 M
Correct classification as Even 1.0 M
Q4 Bead Necklaces & Bundling • Tens and Ones
A craftsman makes bead necklaces. Each necklace contains exactly 10 beads.
(a) How many full necklaces can be made from 85 beads, and how many loose beads are left over?
(b) How many more beads are needed to make one more complete necklace?
(c) Express 85 in standard expanded form.
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
(a) Full Necklaces and Loose Beads:
• Total beads = 85
• Number of tens in 85 = 8 complete necklaces (8 × 10 = 80 beads)
• Loose beads remaining = 85 - 80 = 5 loose beads.

(b) Beads Needed for Next Necklace:
• One necklace requires 10 beads. Currently we have 5 loose beads.
• Needed = 10 - 5 = 5 more beads.

(c) Expanded Form:
• 85 = 8 Tens + 5 Ones = 80 + 5.
CBSE Step-by-Step Marking Scheme
Correct calculation of 8 necklaces and 5 loose beads 1.0 M
Correct beads needed for next necklace (5 beads) 1.0 M
Correct expanded form representation (80 + 5) 1.0 M
Q5 Price Comparison • Toy Shop Rates
Look at the prices of these toys: Toy Car = ₹65, Robot = ₹92, Doll = ₹48, Wooden Train = ₹75.
(a) Arrange the toys in ascending order of their prices (cheapest to costliest).
(b) What is the difference in price between the most expensive toy and the cheapest toy?
(c) Can you buy both the Doll and the Toy Car with a single ₹100 note? Explain with calculation.
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
(a) Ascending Order:
• ₹48 (Doll) < ₹65 (Toy Car) < ₹75 (Wooden Train) < ₹92 (Robot).

(b) Price Difference:
• Costliest = Robot (₹92)
• Cheapest = Doll (₹48)
• Difference = ₹92 - ₹48 = ₹44.

(c) ₹100 Budget Verification:
• Cost of Doll + Toy Car = ₹48 + ₹65 = ₹113.
• Since ₹113 > ₹100, No, you cannot buy both toys with a ₹100 note. You are short by ₹13.
CBSE Step-by-Step Marking Scheme
Correct ascending order arrangement 1.0 M
Correct difference calculation (92 - 48 = 44) 1.0 M
Correct budget calculation (48 + 65 = 113 > 100) 1.0 M
Q6 Coin Combinations • Exact Payment
Rohit wants to buy a toy airplane costing ₹76. He has ₹10 notes and ₹5, ₹2, and ₹1 coins.
(a) Give one combination of notes and coins to make exactly ₹76.
(b) Give another combination using fewer notes and more coins.
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Combinations:
(a) Combination 1 (Standard):
• 7 notes of ₹10 = ₹70
• 1 coin of ₹5 = ₹5
• 1 coin of ₹1 = ₹1
• Total = ₹70 + ₹5 + ₹1 = ₹76.

(b) Combination 2 (More Coins):
• 6 notes of ₹10 = ₹60
• 3 coins of ₹5 = ₹15
• 1 coin of ₹1 = ₹1
• Total = ₹60 + ₹15 + ₹1 = ₹76.
CBSE Step-by-Step Marking Scheme
First valid currency combination summing to ₹76 1.5 M
Second distinct valid currency combination summing to ₹76 1.5 M
Q7 Number Sequences • Toy Train Carriages
Complete the following skip counting sequences written on toy train carriages:
(a) 14, 24, 34, ___, ___, 64
(b) 85, 75, 65, ___, ___, 35
(c) What is the pattern rule in sequence (a) and sequence (b)?
[3 Marks]
✅ Step-by-Step Solution & Working
Solution:
(a) 14, 24, 34, 44, 54, 64.
(b) 85, 75, 65, 55, 45, 35.
(c) Pattern Rules:
• Sequence (a) follows: Add 10 (+10) each time.
• Sequence (b) follows: Subtract 10 (-10) each time.
CBSE Step-by-Step Marking Scheme
Correct blanks in sequence (a): 44, 54 1.0 M
Correct blanks in sequence (b): 55, 45 1.0 M
Correct identification of rules (+10 and -10) 1.0 M
Q8 Textbook Activity • Bundles of Ten
A toy seller has 68 rubber balls. He packs them into packets of 10 balls each.
(a) How many full packets can he make?
(b) How many loose balls will be left over?
(c) How many more balls does he need to complete another packet?
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
• (a) Full packets: 68 has 6 tens. He can make 6 full packets (6 × 10 = 60).
• (b) Loose balls: 68 - 60 = 8 loose balls.
• (c) Balls needed: 10 - 8 = 2 more balls to make the next packet.
CBSE Step-by-Step Marking Scheme
6 packets 1 M
8 loose balls 1 M
2 more balls needed 1 M
Q9 Practice Time • Comparing Toy Prices
In a toy shop: Robot costs ₹75, Car costs ₹45, Drum costs ₹90, and Yo-yo costs ₹20.
(a) Which toy costs the most and which costs the least?
(b) Arrange all 4 toys in order from least expensive to most expensive.
(c) If Raju buys the Car and Yo-yo, how much does he pay?
[3 Marks]
✅ Step-by-Step Solution & Working
Step-by-Step Solution:
• (a) Prices: Most expensive is Drum (₹90); least expensive is Yo-yo (₹20).
• (b) Ascending Order: Yo-yo (₹20) < Car (₹45) < Robot (₹75) < Drum (₹90).
• (c) Total cost: ₹45 + ₹20 = ₹65.
CBSE Step-by-Step Marking Scheme
Drum most expensive, Yo-yo least 1 M
Ascending order 1 M
Total ₹65 1 M
Q10 Number Building • Tens and Ones
Write the numbers represented by:
(a) 4 tens and 7 ones
(b) 8 tens and 0 ones
(c) 9 tens and 9 ones
(d) 5 tens and 14 ones.
[2 Marks]
✅ Step-by-Step Solution & Working
Solutions:
• (a) (4 × 10) + 7 = 40 + 7 = 47.
• (b) (8 × 10) + 0 = 80.
• (c) (9 × 10) + 9 = 90 + 9 = 99.
• (d) (5 × 10) + 14 = 50 + 14 = 64.
CBSE Step-by-Step Marking Scheme
47, 80, 99, 64 correct 2 M
Q11 Money Problems • Paying Exact Amount
A teddy bear costs ₹65. Which combination of currency notes can be used to pay exactly ₹65 without receiving change?
(A) Three ₹20 notes and one ₹5 coin
(B) One ₹50 note, one ₹10 note, and one ₹5 coin
(C) Both A and B are correct.
[2 Marks]
✅ Step-by-Step Solution & Working
Verification:
• Option A: (3 × ₹20) + ₹5 = ₹60 + ₹5 = ₹65.
• Option B: ₹50 + ₹10 + ₹5 = ₹65.
• Therefore, (C) Both A and B are correct.
CBSE Step-by-Step Marking Scheme
Validating both note combinations make ₹65 2 M
Q12 Mental Math • Skip Counting by 10
Count by tens starting from 25: 25, 35, 45, ___, ___, ___, 85, 95.
[2 Marks]
✅ Step-by-Step Solution & Working
Sequence:
Adding 10 at each step:
25, 35, 45, 55, 65, 75, 85, 95.
Missing numbers are 55, 65, 75.
CBSE Step-by-Step Marking Scheme
Correct missing values: 55, 65, 75 2 M
Q13 Word Problem • Toys on Shelves
There are 3 shelves of toys. Shelf 1 has 24 toys, Shelf 2 has 31 toys, and Shelf 3 has 19 toys. How many toys are there in total?
[2 Marks]
✅ Step-by-Step Solution & Working
Addition:
24 + 31 + 19 = 24 + (31 + 19) = 24 + 50 = 74 toys in total.
CBSE Step-by-Step Marking Scheme
Total = 74 toys with working 2 M
Q14 Think & Solve • Finding Difference
Pooja has ₹92. She wants to buy a battery car costing ₹100. How much more money does she need?
[1 Marks]
✅ Step-by-Step Solution & Working
Subtraction:
₹100 - ₹92 = ₹8 more needed.
CBSE Step-by-Step Marking Scheme
₹8 difference 1 M
Q15 Hands-on Activity • Exchanging Coins
How many 5-rupee coins make ₹50? How many 10-rupee notes make ₹100?
[2 Marks]
✅ Step-by-Step Solution & Working
Division:
• ₹50 ÷ ₹5 = 10 coins of 5 rupees.
• ₹100 ÷ ₹10 = 10 notes of 10 rupees.
CBSE Step-by-Step Marking Scheme
10 coins and 10 notes 2 M
Q16 Place Value Puzzle • Mystery Number
I have 7 in my tens place. My ones digit is 3 less than my tens digit. What number am I?
[2 Marks]
✅ Step-by-Step Solution & Working
Deduction:
• Tens digit = 7.
• Ones digit = 7 - 3 = 4.
• Number = 74.
CBSE Step-by-Step Marking Scheme
Number = 74 2 M
Q17 Expanded Form Practice • Decomposing Numbers
Write 83 and 59 in expanded form using tens and ones.
[2 Marks]
✅ Step-by-Step Solution & Working
Expanded Form:
• 83 = 8 Tens + 3 Ones = 80 + 3.
• 59 = 5 Tens + 9 Ones = 50 + 9.
CBSE Step-by-Step Marking Scheme
80 + 3 and 50 + 9 2 M
Q18 Review Questions • Rounding to Nearest 10
Round each number to the nearest ten: (a) 42 (b) 78 (c) 65.
[3 Marks]
✅ Step-by-Step Solution & Working
Rounding Rules:
• (a) 42: Ones digit is 2 (<5), rounds down to 40.
• (b) 78: Ones digit is 8 (≥5), rounds up to 80.
• (c) 65: Ones digit is 5, rounds up to 70.
CBSE Step-by-Step Marking Scheme
40, 80, 70 correct with reasoning 3 M
🌟 NEP 2020 Competency-Based Case Study

Toy Store Clearance Sale

During Diwali sale, the shop offers a 'Buy 2 Get ₹10 Off' coupon on toy purchases above ₹50.

Analytical Task: Arjun selects a toy drum for ₹35 and a toy car for ₹42. Does he qualify for the discount? What is his final bill amount?
Evaluation & Model Answer:
1. Total cost before discount = ₹35 + ₹42 = ₹77.
2. Since ₹77 is greater than ₹50 and he bought 2 toys, Arjun qualifies for the discount.
3. Discount = ₹10.
4. Final bill amount = ₹77 - ₹10 = ₹67.
Rubric: 1M qualification logic + 1M addition + 1M discount subtraction.
⬅️ Ch 1: What's in a Name? Ch 3: Double Century ➡️